Posted by Anonymous Mon 12th Mar 2007 07:46 - Syntax is PHP - 139 views
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PHP parser reported no syntax errors in this post!
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//main
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if ($_SESSION['is_admin'] == 1) {
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}
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else {
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echo "not logged!";
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}
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?>
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/* logout */ session_start(); session_destroy(); header("Location: ../login"); ?>
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// login success script
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include ('../../db/database.php');
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$query = "SELECT COUNT(*) FROM users WHERE user = '$escape_user' AND password=password('$escape_password');";
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$_SESSION['is_admin'] = 1;
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}
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else {
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// error message here.
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}
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?>
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Posted by Anonymous Mon 12th Mar 2007 07:46 - Syntax is PHP - 139 views
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